in two dice game, the player take turns to roll both dice, they can roll as many times as they want in one turn.
Answers
Explanation:
In two dice game, the player take turns to roll both dice, they can roll as many times as they want
in one turn. A player scores the sum of the two dice thrown and gradually reaches a higher score as
they continue to roll. If a single number 1 is thrown on either die, the score for that whole turn is
lost. Two dice are thrown simultaneously
37. What is the probability of getting the sum as an even number ?
(i) ¾ (ii) 1/2 (iii) 1/4 (iv) 5/8
38. What is the probability of getting the sum as a prime number ?
(i) 5/12 (ii) 1/6 (iii) 7/12 (iv) 11/12
39. What is the probability of getting the sum of at least 10?
(i) 5/12 (ii) 5/6 (iii) 1/6 (iv) 7/12
40. What is the probability of getting a doublet of even number ?
(i) 1/12 (ii) 5/12 (iii) 11/12 (iv) 7/12
41. What is the probability of getting a product of numbers greater than 16?
(i) 7/36 (ii) 2/9 (iii) 1/4 (iv) 11/36
Answer:
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Explanation:
Answer
Sample space for total number of possible outcomes
(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),
(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),
(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),
(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),
(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),
(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)
Total number of outcomes =36
(i)
Favorable outcomes for sum as prime are
(1,1),(1,2),(1,4),(1,6),(2,3),(2,3),(2,5),(3,2),(3,4),(4,1),(4,3),(5,2),(5,6),(6,1),(6,5)
Number of favorable outcomes =15
Hence, the probability of getting the sum as a prime number. =
36
15
=
12
5
(ii)
Favorable outcomes for total of atleast 10 are
(4,6),(5,5),(5,6),(6,4),(6,5),(6,6)
Number of favorable outcomes =6
Hence, the probability of getting a total of atleast 10 =
36
6
=
6
1
(iii)
Favorable outcomes for a doublet of even number are
(2,2),(4,4),(6,6)
Number of favorable outcomes =3
Hence, the probability of getting a doublet of even number =
36
3
=
13
1
(iv)
Favorable outcomes for a multiple of 2 on one dice and a multiple of 3 on the other dice are
(2,3),(2,6),(3,2),(3,4),(3,6),(4,3),(4,6),(6,2),(6,3),(6,4),(6,6)
Number of favorable outcomes =11
Hence, the probability of getting a multiple of 2 on one dice and a multiple of 3 on the other dice =
36
11
(v)
Favorable outcomes for getting a multiple of 3 as the sum
(1,2),(1,5),(2,1),(2,4),(3,3),(3,6),(4,2),(4,5),(5,1),(5,4),(6,3)(6,6)
Number of favorable outcomes =12
Hence, the probability of getting a multiple of 3 as the sum =
36
12
=
3
1