Math, asked by kewalmer888, 3 months ago

In two dice game, the player take turns to roll both dice, they can roll as many times as they want

in one turn. A player scores the sum of the two dice thrown and gradually reaches a higher score as

they continue to roll. If a single number 1 is thrown on either die, the score for that whole turn is

lost. Two dice are thrown simultaneously

37. What is the probability of getting the sum as an even number ?

(i) ¾ (ii) 1/2 (iii) 1/4 (iv) 5/8

38. What is the probability of getting the sum as a prime number ?

(i) 5/12 (ii) 1/6 (iii) 7/12 (iv) 11/12

39. What is the probability of getting the sum of at least 10?

(i) 5/12 (ii) 5/6 (iii) 1/6 (iv) 7/12

40. What is the probability of getting a doublet of even number ?

(i) 1/12 (ii) 5/12 (iii) 11/12 (iv) 7/12

41. What is the probability of getting a product of numbers greater than 16?

(i) 7/36 (ii) 2/9 (iii) 1/4 (iv) 11/36​

Answers

Answered by frenzy87
1

Answer:

When a pair of dice is thrown there are 36 possibilities. Starting with 1–2, 1–3, 1–4 … to 6–4, 6–5,6–6.

The pairs of dice thrown that add up to 5 are 1–4. 2–3, 3–2, 4–1

The pairs of dice thrown that add up to 9 are 3–6, 4–5, 5–4, 6–3

So there are 8 possible throws that are successful. 8/36 = 4/18, or 2/9 or a 22.22….% chance of success. This can be rounded out to just over 22%

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