Question

in two digit natural number,the digit at the tens place is equal to the square of unit place.if 54 is subtracted from the number,the digits are interchanged​

Answer 1

Let the digit in the tens place be X and the digit in once place be y
Since x is at tens place therefore it will be

10X+y+54=10y+X
10X+X2+54=10X2+X
After we arrange it
9X2-9X-54=0

Since all no divide by 9
X2-X-6=0
X2 + 2X - 3X - 6 = 0
X(X + 2) - 3(X+2) = 0
(X+2) (X-3) = 0
X+2 = 0 or X-3 = 0
X= -2 or X= 3
X cannot be negative

y = X2

y = 3^2= 9

Since y=9
X=3
No is 39
39 +54=93