in two digit nos the one place exceeds the tens place by 1 and tge product of the given no and its tens place is 280
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Answer:
X=2+Y⟹(i)
And (10Y+X)(X+Y)=144
10XY+10Y
2
+X
2
+XY=144
11XY+10Y
2
+X
2
=144⟹(ii)
Substitute X from (i) in (ii) and get
11(2+Y)Y+10Y
2
+(2+Y)
2
=144
22Y+11Y
2
+10Y
2
+4+4Y+Y
2
=144
22X+11X
2
+40+40X+10X
2
=144
22Y
2
+26Y−140=0
11Y
2
+13Y−70=0
11Y
2
+35Y−22Y−70=0
Y(11Y+35)−2(11Y+35)=0
(y−2)(11Y+35)=0
Now either (Y−2)=0
Y=2
Or 11Y+35=0
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