in two digit number digit at units place is 5 more than the digit at tens place if the number obtained by interchanging the digits is added to original number the sum is 99 then find the number
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Let the tens digit no.=x
Unit digit no.=x+5
no.=10(x+x+5)=10(2x+5)=20x+50
when interchange the no.
10(x+5+x)=10(2x+5)=20+50
20x+50+20x+50=99
40x+100=99
40x=99-100=-1
x=-1\40
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