In two-digit number, first digit is four times of second digit. Adding this to the new number formed by interchanging the digits, 110 is obtained. Find the numbers.
Answers
Answered by
31
Let the no be 10y+x
y=4x......1
10y+x+10x+y=110
11x+11y=110
x+y=10.......2
From 1 and 2
x=2 and y=8
Therefore the no is 10(8)+2=82
Please mark brainliest
y=4x......1
10y+x+10x+y=110
11x+11y=110
x+y=10.......2
From 1 and 2
x=2 and y=8
Therefore the no is 10(8)+2=82
Please mark brainliest
Answered by
3
Number = 82 & Number by interchanging digit = 28
Step-by-step explanation:
Let say two Digit number = AB
, first digit is four times of second digit
=> A = 4B
Value of number = 10A + B
number formed by interchanging the digits = BA
Value = 10B + A
10A + B + 10B + A = 110
=> 11A + 11B = 110
=> A + B = 10
A = 4B
=> 4B + B = 10
=> 5B = 10
=> B = 2
A = 4B = 8
Number = 82
Number by interchanging digit = 28
Learn more:
The sum of two digit number formed by interchanging the digit is 132 ...
https://brainly.in/question/8039460
The sum of two digit number and the number formed by ...
https://brainly.in/question/7732267
Sum of the digit of a two digit is 9 when we interchanges the digits it ...
https://brainly.in/question/7431076
Similar questions