Question

In two digit number, if digit at tens place is 8 and sum of the digit is nine times than digit at unit place,
then number is______.​

Answer 1

Step-by-step explanation:

hence x=9

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Answer 2

The number is 81.

Step-by-step explanation:

Let the unit digit be 'x'

Digit at tens place = 8

Sum of digits = 8+x

it is 9 times than digit at unit place,

So, it becomes,

$8+x=9x\\\\8=9x-x\\\\8=8x\\\\x=\dfrac{8}{8}=1$

So, the number is 81.

# learn more:

In two digit number, if digit at tens place is 8 and sum of the digit is nine times than digit at unit place,then number is____81__.​

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