Question

In two digit number, if digit at tens place is 8 and sum of the digit is nine times than digit at unit place,then number is____81__.​

Answer 1

Answer:

tens place digit = 8

let the digit at units place be x

so, sum of two digits = 9 times x

sum of both the digits = 9x

8+x = 9x

8 = 9x-x

8x = 8

x = 8/8

x = 1

so, digit at units place = 1

digit at tens place = 8

number thus formed = 81

hope it helps

have a nice day