In two digit number is 4 times that sum of digit when 9 is added to the number the digit will get revised reverse
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Hlw mate!!
All 2-digit numbers are in the form 10a+b
The following 2 equations are derived from the question:
10a+b = 4(a+b)
10a+b+18=10b+a
Let’s simplify the first equation:
10a+b = 4(a+b)
10a+b = 4a+4b
6a = 3b
2a = b
Now, we know the possible values of a and b:
[a=1, b=2], [a=2, b=4], [a=3, b=6], [a=4, b=8]
Now, we can use trial and error with the second equation, by substituting in the possible values of a and b:
[a=1, b=2]: 12 + 18 ≠ 21
[a=2, b=4]: 24 + 18 = 42
Above is a number which fulfills the requirements, 24. However, we must check to be sure that there are no other possible solutions.
[a=3, b=6]: 36 + 18 ≠ 63
[a=4, b=8]: 48 + 18 ≠ 84
The above values of a and b do not fulfill the requirements.
The number is of form 10a+b where a=2 and b=4, so the number is 24.
Hope it helpful
All 2-digit numbers are in the form 10a+b
The following 2 equations are derived from the question:
10a+b = 4(a+b)
10a+b+18=10b+a
Let’s simplify the first equation:
10a+b = 4(a+b)
10a+b = 4a+4b
6a = 3b
2a = b
Now, we know the possible values of a and b:
[a=1, b=2], [a=2, b=4], [a=3, b=6], [a=4, b=8]
Now, we can use trial and error with the second equation, by substituting in the possible values of a and b:
[a=1, b=2]: 12 + 18 ≠ 21
[a=2, b=4]: 24 + 18 = 42
Above is a number which fulfills the requirements, 24. However, we must check to be sure that there are no other possible solutions.
[a=3, b=6]: 36 + 18 ≠ 63
[a=4, b=8]: 48 + 18 ≠ 84
The above values of a and b do not fulfill the requirements.
The number is of form 10a+b where a=2 and b=4, so the number is 24.
Hope it helpful
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