Question

In two digit number the digit in the unit place is two more than the three times of the digit in tens place if the sum of two digits is 6, what is the number

Answer 1

Let the ten's and unit's digit be x and y respectively.

Given

The digit in the unit place is two more than the three times of the digit in tens place.

$\implies y = 3x+2\\\implies y-3x=2\\\implies 3x-y = -2 --(1)$

The sum of the digits is 6

$\implies x+y=6--(2)$

Solving (1) and (2) we get,

$3x-y=-2\\\underline{x+y=6}\\\underline{\underline{4x=4}}\\\implies x = 1$

$\implies y = 5$

$\boxed{\boxed{\bold{Therefore, \ the \ number \ is \ 15}}}}$

                                                         

Answer 2

Answer:

Let the ten's and unit's digit be a and b

⋆ Number Formed : (10a + b)

☆ According to the First Statement :

⇾ Unit's Digit = 3(Ten's Digit) + 2

⇾ b = 3a + 2 ⠀⠀— eq. ( I )

━━━━━━━━━━━

☢ According to the Second Statement :

⇢ Sum of Digits = 6

⇢ a + b = 6

• Putting value of b from eq. ( I )

⇢ a + 3a + 2 = 6

⇢ 4a = 6 – 2

⇢ 4a = 4

• Dividing both term by 4

⇢ a = 1

____________________

☢ Putting value of a in eq. ( I ) :

⇢ b = 3a + 2

⇢ b = 3(1) + 2

⇢ b = 3 + 2

⇢ b = 5

∴ Therefore, Number formed will be 15.