Question

In two digit number ,the digit in unit place is 10x and digit in ten's place is y. find the two digit number.



plz anyone solve it .​

Answer 1

Step-by-step explanation:

Let the number be 10x + y, where x is the tens place digit and y be the units place digit. Given, the digit at the units place is thrice the digit in the tens place. Also given, the number exceeds the sum of its digits by 27. Therefore, the required number is 10 × 3 + 9 = 30 + 9 = 39.

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