In two digit number what is the probability of getting multiple of 3 and not multiple of 5
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There are 90 two digit numbers(99–9).
Out of this there are 6 numbers divisible by 15(15, 30, 45, 60, 75, 90), which are also divisible by 5.
Therefore, the favorable cases are 30–6=24.
Hence, the required probability is 24/90 = 4/15.
Out of this there are 6 numbers divisible by 15(15, 30, 45, 60, 75, 90), which are also divisible by 5.
Therefore, the favorable cases are 30–6=24.
Hence, the required probability is 24/90 = 4/15.
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