Question

In two digit numbers the units digit is thrice the tens digit .if 36 is adder to the number ,the digit interchange their place.find the number. ​

Answer 1

Answer:

Let say 'x' is digit in one's place so 3x is digit in tens place.

So number is 10.3x+x=31x

Now if interchanging the position of digit new number is 10x+3x=13x

As given now number is less than 54 from old number.

31x−54=13x

⇒31x−13x=54

⇒18x=54

⇒x=54/18

⇒x=3

So, the number is 10.3.3+3=93

∴ The original number is 93.

solution

Answer 2

Let the ones digit be x

And the tens digit be 10y

The number = x + 10y

ATGC

x = 3*10y

x = 30y___(1)

Also

x + 10y + 36 = 10x + y

Put value of x = 30y

30y + 10 y + 36 = 300y + y

40y + 36 = 301 y

36 = 301y - 40 y

36 = 241 y

Y = 36/241

x = 30 * 36/241

Put values of x and y in

x + 10 y to get the number