In two linear equations a1x+b1y+C1=0 and a2x+b2y+c2=0.
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Given a1x+b1y+c1=0........1
a2x+b2y+c2=0......2
from (1) we have
c= -by-ax..........3
from (1) and (2) we have
a1x+b1y+c1=0
a2x+b2y+c2=0
___________
a3x+b3y+3c=0
Now using (3)
a3x+b3y+3(-by-ax) =0
a3x+b3y-3 by-3ax=0
0=0
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