In two right triangles PQR and XYZ, side PQ=sideXY, side QR= side YZ.
By which congruent criterion, are the two triangles congruent?
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Answer:
Step-by-step explanation:
△ABC and△PQR in which AB=PQ,BC=QR and AM=PN.
Since AM and PN are median of triangles ABC and PQR respectively.
Now, BC=QR ∣ Given
⇒
2
1
BC=
2
1
QR ∣ Median divides opposite sides in two equal parts
BM=QN... (1)
Now, in △ABM and△PQN we have
AB=PQ ∣ Given
BM=QN ∣ From (i)
and AM=PN ∣ Given
∴ By SSS criterion of congruence, we have
△ABM≅△PQN, which proves (i)
∠B=∠Q ... (2) ∣ Since, corresponding parts of the congruent triangle are equal
Now, in △ABC and△PQR we have
AB=PQ ∣ Given
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