Question

In two similar triangles PQR and LMN, QR = 15 cm and MN = 10 cm. Find the ratio of the areas

of the triangles.

Answer 1

Answer:

9:4

Step-by-step explanation:

A(triangle PQR)/A(triangle LMN)=(QR/MN)^2

                                                    =(15/10)^2                                      

                          A(PQR)/A(LMN) =9/4

Answer 2

The ratio of the areas  of the triangles is 9:4

Step-by-step explanation:

Side of triangle PQR = QR = 15 cm

Side of triangle of LMN = MN = 10 cm

Theorem : the ratio of the area of two similar triangles is equal to the ratio of the square of the corresponding sides of similar triangles .

So,$\frac{\text{Area of triangkle PQR}}{\text{Area of triangle LMN}}=\frac{QR^2}{MN^2}$

$\frac{\text{Area of triangkle PQR}}{\text{Area of triangle LMN}}=\frac{15^2}{10^2}$

$\frac{\text{Area of triangkle PQR}}{\text{Area of triangle LMN}}=\frac{15^2}{10^2}=\frac{9}{4}$

Hence the ratio of the areas  of the triangles is 9:4

#Learn more:

If triangle ABC is similar to PQR BC=8 cm and QR= 6cm. Find the ratio of their areas

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