Question

In two triangles DEF and PQR, if DE = QR, EF = PR and FD = PQ, then
(1 Point)
∆DEF ≅ ∆PQR
∆FED≅ ∆PRO
∆EDF ≅ ∆RPQ
∆EFD≅ ∆PQR​

Answer 1

Question

In two triangles DEF and PQR, if DE = QR, EF = PR and FD = PQ

then

• ∆DEF ≅ ∆PQR
• ∆FED≅ ∆PRQ
• ∆EDF ≅ ∆RPQ
• ∆EFD≅ ∆PQR​

Explanation

First, we could try this:

• Drawing a diagram.

I will attach a diagram here. So please refer to the attachment.

Extra explanation

DE = QR, EF = PR

We can see that point E is common.

And point R is common in both equations.

So point E will correspond to point R.

EF = PR, FD = PQ

In the same manner, we see point F corresponding to point P.