In two triangles PQR and DEF, if PQ= DE, QR=EF and congruency rule is
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Answer:
IF ∆PQR and ∆DEF
PQ=DE (Given)
QR=EF (Given)
QE=QE (Common sides)
Thus, ∆POQ~Is Congurent to ~∆DEF
(OwO)
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Answer:
Given: PR=EF, QR=DE and PQ=FD
Now, In △PRQ and △DEF
PR=EF
QR=DE
PQ=FD
Thus, △PQR≅△FDE (SSS rule)
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