Question

In unknown organic compound % of c=40,o=53.4%,H=6.66% if vapour density is 90 find empidical and molecular formula NOT SPAM OK GUYS ​

Answer 1

Answer:

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Explanation:

Percentage oxygen = 100- ( 40+ 6.66)= 100 - 46.6 = 53.4%  

Hence, empirical formula = CH20

Now, empirical formula mass  

=12+(2×1)+16=12+2+16=30  

Molecular mass of given organic compound = vapor density x 2 = 30 x 2 = 60

n = Molecular mass / Empirical formula mass = 60/30=2

Thus , Molecular formula = (Empirical formula) ×n=(CH20) x 2 = c2h4o2  

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