In usual notations prove that (A U B) U C = A U (B U C)
Answers
Answer:
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Step-by-step explanation:
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SOLUTION
TO PROVE
In usual notations prove that
(A U B) U C = A U (B U C)
PROVE
Let x ∈ ( A U B ) U C
⟹ x ∈ ( A ∨ B ) ∨ C
⟹ x ∈ A ∨ B ∨ C
⟹ x ∈ A ∨ ( B ∨ C )
⟹ x ∈ A U (B U C)
∴ (A U B) U C ⊆ A U (B U C) - - - - - - - (1)
Let y ∈ A U ( B U C )
⟹ y ∈ A ∨ ( B ∨ C )
⟹ y ∈ A ∨ B ∨ C
⟹ y ∈ ( A ∨ B ) ∨ C )
⟹ y ∈ ( A U B ) U C
∴ A U (B U C) ⊆ (A U B) U C - - - - - - - (2)
From (1) & (2) we get
(A U B) U C = A U (B U C)
Hence proved
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