in vessel P 150 litre of petrol and in vessel Q 150 litre of kerosene if 30 liter from P is taken and poured into Q and again 30 liter taken from Q and poured into P .this process repeated once again .find ratio of petrol and kerosene in P at the end
Answers
13:5 is the ratio of petrol and kerosene in P.
Step-by-step explanation:
Given,
P = 150 l petrol, Q = 150 l Kerosene
ATQ,
Pouring 30 liters from P to Q,
Now, In Q = 150 liters Kerosene + 30 liter petrol
In P, 150 liters petrol - 30 Liters = 120 liters petrol
∵ Kerosene/Petrol = 150/30 = 5:1
Now Pouring 30l from Q to P,
∵ In that 30 Liters,
Petrol = 1/(5 + 1) * 30 = 5liters
Kerosene = 5/6 * 30 = 25liters
Now, In Q = 125 liters Kerosene + 25liters
In P = 125 liters Petrol, 25 liters Kerosene
∵ K:P = 5:1 & P:K = 5:1
Now again 30 liters from P to Q,
In that 30liters = Petrol = 5/(1 + 5) * 30 = 25liters
Kerosene = 1/(1 + 5) * 30 = 5liters
∵ In Q = 130 liters Kerosene + 50 liters petrol
In P = 100 liters petrol + 20 liters Kerosene
Thus, K:P = 13:5 & P:K = 5:1
Now again, 30 liters from Q to P;
∵ In that 30 liters;
Petrol = 5/(13 + 5) * 30 = 25/3 liters
Kerosene = 13/18 * 30 = 65/3 liters
In P,
Petrol = 100 + 25/3 = 325/3 liters
Kerosene = 20 + 65/3 = 125/3 liters
∵ P:K = 325/3 ÷ 125/3 = 13:5
Thus, the ratio of petrol and kerosene in P at the end is 13:5.
Learn more: find the ratio
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