Question

In victor meyer’s experiment, 0.6g of a volatile substance displaced 112ml of air at STP. Find the molecular mass of the substance.​

Answer 1

Answer:

Answer:Volume occupied by solute at NTP = Volume of air displaced at NTP = 112 ml

Answer:Volume occupied by solute at NTP = Volume of air displaced at NTP = 112 mlFor volatile solute

Answer:Volume occupied by solute at NTP = Volume of air displaced at NTP = 112 mlFor volatile solute$PV= < /p > < p > \frac{MRT}{times} < /p > < p >[tex]PV=</p><p> </u></em></strong></p><p><strong><em><u>Answer:Volume occupied by solute at NTP = Volume of air displaced at NTP = 112 mlFor volatile solute[tex] PV= < /p > < p > \frac{MRT}{times} < /p > < p >[tex]PV=</p><p> times</u></em></strong></p><p><strong><em><u>Answer:Volume occupied by solute at NTP = Volume of air displaced at NTP = 112 mlFor volatile solute[tex] PV= < /p > < p > \frac{MRT}{times} < /p > < p >[tex]PV=</p><p> timesMRT</u></em></strong></p><p><strong><em><u>Answer:Volume occupied by solute at NTP = Volume of air displaced at NTP = 112 mlFor volatile solute[tex] PV= < /p > < p > \frac{MRT}{times} < /p > < p >[tex]PV=</p><p> timesMRT </u></em></strong></p><p><strong><em><u>Answer:Volume occupied by solute at NTP = Volume of air displaced at NTP = 112 mlFor volatile solute[tex] PV= < /p > < p > \frac{MRT}{times} < /p > < p >[tex]PV=</p><p> timesMRT </p><p>$

Answer:Volume occupied by solute at NTP = Volume of air displaced at NTP = 112 mlFor volatile solute$PV= < /p > < p > \frac{MRT}{times} < /p > < p >[tex]PV=</p><p> timesMRT </p><p>$At NTP, P=1atm,T=273K

Answer:Volume occupied by solute at NTP = Volume of air displaced at NTP = 112 mlFor volatile solute$PV= < /p > < p > \frac{MRT}{times} < /p > < p >[tex]PV=</p><p> timesMRT </p><p>$At NTP, P=1atm,T=273K1∗ < /p > < p > 1000 < /p > < p > 112 < /p > < p > < /p > < p > = < /p > < p > m < /p > < p > 0.23 < /p > < p > < /p > < p > ∗0.0821∗2731∗</p><p>1000</p><p>112</p><p></p><p>=</p><p>m</p><p>0.23</p><p></p><p>∗0.0821∗273

Answer:Volume occupied by solute at NTP = Volume of air displaced at NTP = 112 mlFor volatile solute$PV= < /p > < p > \frac{MRT}{times} < /p > < p >[tex]PV=</p><p> timesMRT </p><p>$At NTP, P=1atm,T=273K1∗ < /p > < p > 1000 < /p > < p > 112 < /p > < p > < /p > < p > = < /p > < p > m < /p > < p > 0.23 < /p > < p > < /p > < p > ∗0.0821∗2731∗</p><p>1000</p><p>112</p><p></p><p>=</p><p>m</p><p>0.23</p><p></p><p>∗0.0821∗273m = 46.02 and V.D. = 23.01m=46.02andV.D.=23.01

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