Question

In volumetric analysis it was found that 100 ml of Hcl solution neutralized 50 ml of sodium carbonate solution The hcl solution contains 3.65 gm hcl per liter calculate the concentration of sodium carbonate in solution in terms of normality and molarity

Answer 1

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Given :

Heat gained = 4.5 × 10⁵ J

Heat released = 2 × 10⁵ J

To Find :

Percentage efficiency of steam engine and work done per cycle..

Solution :

❒ Efficiency of a heat engine/steam engine is given by, η = 1 - (Q₂ / Q₁)

Where,

η denotes efficiency

Q₂ denotes heat released to the sink

Q₁ denotes heat extracted from the source

By substituting the given values;

➛ η = 1 - (Q₂ / Q₁)

➛ η = 1 - (2 × 10⁵ / 4.5 × 10⁵)

➛ η = 1 - 0.44

➛ η = 0.56

Percentage efficiency = 56%

❒ Work done per cycle :

We know that work done is measured as the change in energy.

➠ W = Q₁ - Q₂

➠ W = (4.5 × 10⁵) - (2 × 10⁵)

➠ W = 2.5 × 10⁵ J

Answer 2

Answer:

In volumetric analysis it was found that 100 ml of Hcl solution neutralized 50 ml of sodium carbonate solution The hcl solution contains 3.65 gm hcl per liter calculate the concentration of sodium carbonate in solution in terms of normality and molarity