Question

In ΔVWX, \overline{VX}

VX

is extended through point X to point Y, \text{m}\angle VWX = (x+14)^{\circ}m∠VWX=(x+14)

∘

, \text{m}\angle XVW = (x+9)^{\circ}m∠XVW=(x+9)

∘

, and \text{m}\angle WXY = (5x-10)^{\circ}m∠WXY=(5x−10)

∘

. What is the value of x?x?

Answer 1

Answer:

ok here's the answer (mark as Brainliest answer)

Step-by-step explanation:

Explanation:

Given the mass of the body, m= 30 kg.

The momentum of the body, p = 150 kg m/s.

We have to calculate the velocity of the body.

The momentum is given as,

p =m x v.

here, v is the velocity of the body.

substitute the given values, we get

150kg.m/s=30kg\times v150kg.m/s=30kg×v

v=\frac{150kg.m/s}{30kg}v=

30kg

150kg.m/s

v = 5 m/s.

Thus, the velocity of the body is 5 m/s.

#Learn More: momentum.

Answer 2

The answer is given below.

The centre of mass of the apple is 25 cm from the pivot and the centre of mass of the weight is 45 cm from the pivot.

(i) the weight of the apple

(ii) the mass of the apple.

(c) The apple is not moved. The weight is removed from the rule and the pivot is moved to the left until the rule balances as given.

• The pivot is closer to the 50 cm mark than to the centre of mass of the apple.Compare the weight of the rule to the weight of the apple.
• The value of x is (5x - 10)