Chemistry, asked by prashantkhodke, 4 months ago

In water molecule the normal tetrahedrall angle has
decreased by

Answers

Answered by Anonymous

Explanation:

In water, H−O−H bond angle decreases from 109. 5o to 104. 5o as lone pair-lone pair repulsion is more than bond pair-bond pair repulsion and lone pair-bond pair repulsion.

Answered by rahul1234567898

Answer:

In water, H−O−H bond angle decreases from 109. 5o to 104. 5o as lone pair-lone pair repulsion is more than bond pair-bond pair repulsion and lone pair-bond pair repulsion. How satisfied are you with the answer?

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