In wave mass doesn't transfer so that we can see that mass = 0
but ,
from the formula E = mc²
if mass = 0
energy will 0
so my question is then How is energy transfer in Wave ?
is this violate E = mc² ??
Answers
Well, E = mc² will not get violated. This relation is always appropriate but somewhere it becomes a little bit small accurate.
The first thing will be the thought of you. You can think this in two ways - (A) THEORETICALLY and (B) PRACTICALLY.
On theoretical thinking, if mass becomes zero and energy will consequently become zero.
But, practically thinking, which is the actual way to prepare a logic for the answer, should be :
(1) The mass of any body could never be zero. Mass is the amount of matter contained in a body and hence, every substance (whether it is solid, liquid or gas is a kind of matter). Hence, everybody have certain mass. Ultimately, their is no way of violation of E = mc², since a body should have certain mass.
Answer:
The actual formula for E is not E = mc² . This was not the complete equation .
Infact the complete equation is as laid down by Einstein :-
E² = m²c⁴ + p²c²
Explanation:
Here is what will happen when m will be 0 .
E² = m²c⁴ + p²c²
= E² = p²c²
= E = pc
The momentum and the speed of light here matters .
Hence the energy transfer will still depend on the momentum and the speed of light .
E ∝ p .
E ∝ c .
We can also use the above formula to prove that the mass of a photon is zero .
E = √( m²c⁴ + p²c² )
= E = √( m²c⁴ + p²c² )
When the photon is at rest , momentum ( p ) = 0 .
= E = mc²
= m = E/c²
When the photon is at rest , rest energy is 0 .
= m = 0 / c²
= m = 0
Hence photons are massless .
The actual fact is that mass can be zero and even negative !
It does not violate any law .
In fact one scientist prepared a substance with negative mass called antimatter .