In what proportion can three varieties of sugar costing Rs. 20, Rs. 24 and Rs. 36 per kg be mixed so that the price of the mixture is Rs. 28 per Kg?
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cost of sugar 1 = 20 Rs/kg
cost of sugar 2 = 24 Rs/kg
cost of sugar 3 = 36 Rs/kg
consider the proportion as x:y:z
given, x+y+z = 1(kg)
so 20x+ 24y+ 36z = 28
on solving ,
20x+20y+20z+4y+16z= 28 ==> 4y+16z=8
==> y+4z= 2--(1)
similarly , 20x+ 24y+24z+4x-4x+12z = 28
==> 12z-4x = 4 ==> 3z-x= 1---(2)
36x+36y+36z-16x-12y = 28 ==> -16x-12y = -8
==> 4x-3y = 2---(3)
on solving (1) , (2) and (3) ,
we get x= 1/2 , y=0 , z= 1/2
so the proportion can be 1/2:0:1/2
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