Math, asked by janardhanancp19, 9 months ago

In what proportion must sugar at Rs.16.60 a kg be mixed with sugar at Rs.16.45 a kg s that the mixture may be worth Rs.16.54 a kg?

Answers

Answered by DebranjanKhanda
4

Answer:

Step-by-step explanation:

16.60 16.45

16.54

(16.54-16.45) (16.60-16.54)

=0.09 : = 0.06

So, 0.09 : 0.06

= 0.09/0.06

=9/6

=3/2

In 3:2 proportion mixture may be worth 16.54 a kg.

Answered by Dhruv4886
0

The proportion of sugar at Rs.16.60 a kg and sugar at Rs.16.45 a kg is

3 : 2

Given problem:

In what proportion sugar at Rs.16.60 a kg be mixed with sugar at Rs.16.45 a kg so that the mixture may be worth Rs.16.54 a kg

Solution:

Let x kg be a quantity of sugar with 16.60 Rs per kg

⇒ Cost of x kg sugar at 16.60 Rs = 16.60x Rs

Let y kg be a quantity of sugar with 16.45 Rs per kg

⇒ Cost of y kg sugar at 16.45 Rs = 16.45y Rs

Assum after mixing x kg of sugar and y kg of sugar then the mixture worth 16.54 Rs.

⇒  16.60x + 16.45y = 16.54 (x+y)

⇒ 16.60x + 16.45y = 16.54x + 16.54y

⇒ 16.60x - 16.54x = 16.54y - 16.45y

⇒ 0.06 x = 0.09 y  

⇒ 6x = 9y [ multiply with 100 on both sides ]

⇒ 2x = 3y  [ divided by 3 ]

\frac{x}{y} = \frac{3}{2}

⇒ x : y = 3 : 2

The proportion of mixtures must in 3 : 2

#SPJ2

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