Question

In what ratio does the line x-5y + 15 = 0 divide the join of A(2,1) and B(-3,6)? Also find the coordinates of their point of intersection. plz answer ASAP

Answer 1

◀  HEY THERE!◀

◀  Question: ◀

→  In what ratio does the line x-5y + 15 = 0 divide the join of A(2,1) and B(-3,6)? Also find the coordinates of their point of intersection.?→

◀  Method of Solution: ◀

→  Given: →

→  Equation: x-5y + 15 = 0

→  Coordinates A(2,1) and B(-3,6)

◀  Solution:◀

→ Let the Required Ratio be k:1

Then, The point of division is (-3k+2/k+1 , 6k+1/k+1)

This point lies on Equation: x-5y + 15 = 0

→  Substitute the value of x and y in Equation!

x-5y + 15 = 0

⇒  (-3k+2/k+1)- 5(6k+1/k+1)=-15

⇒  (-3k+2/k+1) - 30k-5/k+1 = -15

⇒   -3k+2-30k-5/k+1 =-15

⇒   -33k-3/k+1 =-15

⇒   -33k-3=-15(k+1)

⇒    -33k - 3 =-15k-15

 ⇒    -33k+15k=-15+3

 ⇒   -18k=-12

⇒  k=12/18

⇒   •°• k=2/3

→ Hence, Required Ratio k:1 = 2/3:1 => 2:3

◀  Hence, Required coordinates of their point of intersection is 2:3 ◀

Answer 2

Answer:

Step-by-step explanation:

h