Question

In what ratio does the line
x-y-2 = 0 divide the line segment
joining the points A(3, -1) and B(8, 9)?​

Answer 1

Answer:

answer is 2:3

Step-by-step explanation:

Let the ratio be k:1

P [ k(8)+1(3)/k+1 , k(9)+1(-1)/k+1]

P [8k+3/k+1 , 9k-1/k+1]

so, x = 8k+3/k+1 and y = 9k-1/ k+1

x-y-2=0

x-y= 2

put the values of x and y in equation,

x-y=2

(8k+3/k+1) - ( 9k-1/k+1)=2

8k+3-9k-1/k+1=2

-k+4=2k+2

4-2= 2k+k

2=3k

k= 2/3

k/1= 2/3

so, k:1= 2:3