in what ratio does the line x-y-2=0 divides the line segment joining the points a(3 -1) and b(8 9)
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Answer:
Take (-6,10) as A, (3,-8) as B, and (-4,6) as C.
Let the ratio that point C divides AB into be m1:m2
By the section formula,
(-4,6) =
(-4,6) = (3m-6n/m+n, -8m+10n/m+n)
-4 = 3m-6n/m+n
Cross-Multiply to get:
-4(m+n) = 3m - 6n
-4m-4n = 3m - 6n
-7m = -2n
7m = 2n
m:n = 2:7
Therefore the required ratio is 2:7.
Step-by-step explanation:
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