In what ratio does the point (0, 1) divides the line segment joining the points (-1,0) and (2, 3)?
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Answer :
- 2 : 1 is the required ratio.
Given :
- A(-1,0)
- B(2,3)
- C(0,1)
To find :
- In what ratio does the point C divides the line segment joining A and B.
Solution :
Using section formula:
x = [m_1x_2 + m_2x_1/m_1 + m_2]
x(0) = m_1(2) + m_2(-1)/m_1 + m_2]
=> 0 = 2m_1 - 1m_2/m_1 + m_2
=> 0(m_1 + m_2) = 2m_1 - 1m_2
=> 0 = 2m_1 - 1m_2
=> -2m_1 = -1m_2
=> 2m_1 = 1m_2
=> m_1/m_2 = 2/1
or,
y = [m_1y_2 + m_2y_1/m_1 + m_2]
y(1) = m_2(3) + m_2(0)/m_1 + m_2]
=> 1 = 3m_2 + 0m_2/m_1 + m_2
=> m_1 + m_2 = 3m_2 + 0
=> m_1 = 3m_2 - m_2
=> m_1 = 2m_2
=> m_1/m_2 = 2/1
∴ m_1 : m_2 = 2 : 1.
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