in what ratio does the point (-4,6) divide the line segment joining the points A(-6,10) and B (3,8)
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Answers
Answered by
22
Answer:
2:7
Step-by-step explanation:
Let P(-4,6) divided AB in the ratio k : 1.
Here, (x₁,y₁) = (-6,10), (x₂,y₂) = (3,8), m = k, n = 1.
Section formula:
Coordinates of P = (3k - 6/k + 1, -8k + 4/k + 1)
⇒ (-4,6) = (3k - 6/k + 1, -8k + 4/k + 1).
So,
⇒ -4 = (3k - 6)/(k + 1)
⇒ -4(k + 1) = 3k - 6
⇒ -4k - 4 = 3k - 6
⇒ -4k - 3k = -6 + 4
⇒ -7k = -2
⇒ k = 2/7.
Therefore, the ratio is 2:7.
Hope it helps!
KarishmaDhingra:
yeh second step mai -8k kaise aaaya ques.mai toh 8 h sirf
Answered by
12
Step-by-step explanation:
Let the point (-4,6) be M and the ratio in which it divides the line segment be k:1
By section formula the coordinates of the point M are
(-6+3k/k+1,10-8k/k+1)
But M is (-4,6)
-6+3k/k+1=-4
7k=2
k=2/7
Therefore the ratio is 2:7
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