in what ratio does the point (-4,6) divides the line passing through P(2,5) and Q(x,3)
Answers
Answered by
0
Step-by-step explanation:
Using the section formula, if a point (x,y) divides the line joining the points (x
1
,y
1
) and (x
2
,y
2
) in the ratio m:n, then
(x,y)=(
m+n
mx
2
+nx
1
,
m+n
my
2
+ny
1
)
Let the required ratio be m:n
A(−6,10)=(x
1
,y
1
) and B(3,−8)=(x
2
,y
2
)
we have,
(
m+n
mx
2
+nx
1
,
m+n
my
2
+ny
1
)=(−4,6)
⇒
m+n
mx
2
+nx
1
=−4
⇒m(3)+n(−6)=−4m−4n
⇒3m−6n=−4m−4n
⇒3m+4m=6n−4n
⇒7m=2n
⇒
n
m
=
7
2
⇒m:n=2:7
Similar questions