In what ratio does the point p(-4,6) divide the line segment joining the points A(-6,10) and B(3,-8)
Answers
Answer:
2: 7
Step-by-step explanation:
Given,
P = (-4 , 6)
A = (-6 , 10)
B = (3 , - 8)
To Find :-
Ratio that P divides line segment AB .
How To Do :-
We need to consider that ratio as 'm : n' as we need apply the section(internal division ) formula to find the ratio in that we need to substitute the values of the Co-ordinates P, A, B.
Formula Required :-
Section(internal division) formula :-
Solution :-
Let the ratio be 'm : n'
P = (-4 , 6)
Let,
x = - 4 , y = 6
A = (-6 , 10)
Let,
x_1 = - 6 , y_1 = 10
B = (3 , - 8)
Let,
x_2 = 3 , y_2 = - 8
Substituting the values in the formula :-
Equating both x - co-ordinates and y-co - ordinates :-
First equating x co-ordinates :-
-4 = 3m - 6n/m + n
-4(m + n) = 3m - 6n
- 4m - 4n = 3m - 6n
- 4m - 3m = - 6n + 4n
- 7m = - 2n
m/n = - 2/7
m/n = 2/7
m : n = 2 : 7
Equation y co-ordinates :-
6 = -8m + 10n/ m + n
6(m + n) = -8m + 10n
6m + 6n = - 8m + 10n
6m + 8m = 10n - 6n
14m = 4n
m/n = 4/14
m/n = 2/7
m : n = 2 : 7
We can observe that both the ratios are same .
∴ m : n = 2 : 7