Question

In what ratio does the x-axis cut the line segment joining( 5,8) and (7, -3)?

Answer 1

Answer:

by section formula,

m:n=k:1 assume

(mx2+nx1/m+n) , (my2+ ny1/m+n)

(7k+5/k+1) , (-3k+8/k+1) ..... (1)

as the equation cuts x axis the point is(x, 0)...(2)

thus comparing (1) and(2)

(-3k+8/k+1) =0

-3k +8=0

8=3k

k=8/3

k:1=8:3

thus the ratio m:n =8:3