Question

In what ratio does the x-axis divide the line segment joining A(5,6) and B(2,-8)

Answer 1

by using slope formula=

Answer 2

The required ratio is 3:4.

Explanation:

Let the point of x-axis that divides the line segment that joins A(5,6) and B(2,-8) be (x,0).

Let the ratio be k:1.

Then , by Section formula , we have

$(x,0)=(\dfrac{2k+5}{k+1},\dfrac{-8k+6}{k+1})\\\\\Rightarrow\ 0=\dfrac{-8k+6}{k+1}\\\\\Rightarrow\ -8k+6=0\\\\\Rightarrow\ 8k=6\\\\\Rightarrow\ k=\dfrac{6}{8}=\dfrac{3}{4}$

Hence, the required ratio is 3:4.

# Learn more :

The ratio in which X axis divides the line segment joining (2-3) and (5,6)

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