Question

In+what+ratio+does+the+x+axis+divide+the+line+segment+joining+the+points+(2,-3)+and+(5,6)?

Answer 1

Answer:

$\frac{m_{1} }{m_{2} } = \frac{1}{2}$

Step-by-step explanation:

Let us say the point on X axis is (x,0). (As this point was on X-axis the Y co-ordinate will always be zero

Now let us say two points are $(x_{1} ,y_{1})  and (x_{2} ,y_{2})$

Which are (2,-3) and (5,6)

Using the formula $[tex]0=  \frac{m_{1}(6)+m_{2} (-3)}{m_{1}+m_{2}}\\\\0[{m_{1}+m_{2}] = {m_{1}(6)+m_{2} (-3)}\\\\\\0= {m_{1}(6)+m_{2} (-3)\\3m_{2} = 6m_{1}\\\\\\\frac{3}{6} = \frac{m_{1} }{m_{2} } \\\\\frac{1}{2}  = \frac{m_{1} }{m_{2} }$[/tex]