Question

in what ratio does x-axis divide the join A(2, -3) B(5, 6)​

Answer 1

Step-by-step explanation:

Let the ratio be m1:m2

coordinates of x axis=(0,0)

[(m1x2 + m2x1)/(m1+m2),(m1y2 + m2y1)/(m1+m2)]=(0,0)

=>[(5m1 + 2m2)/(m1+m2),(6m1 - 3m2)/(m1+m2)]=(0,0)

=>(5m1+2m2)/m1+m2=0

=>5m1+2m2=0

=>m1/m2= -2/5