Question

in what ratio is tge line joining the points (9, 2) and (-3, - 2 ) divided by the y axis? also find the coordinate of the point of intersection.​

Answer 1

Answer:

ratio is 1:3

Step-by-step explanation:

Answer 2

Question :--- in what ratio is tge line joining the points (9, 2) and (-3, - 2 ) divided by the y axis? also find the coordinate of the point of intersection.

Solution :----

Let the required point be P( 0, y) as the point lies on y-axis.

Also,

let the required ratio be k : 1 ...

Using section formula,

P(0,y) = [(m1*x2+m2*x1) /m1+m2 , (m1*y2 +m2*y1) /m1+ m2]

Substituting values m1=k , m2=1, x1= 9 ,x2= -3 , y1=2, y2=-2,

We get,,

P(0,y) = [ (-3*k +1*9)/ k+1 , (-2*k +1*2) /k+1]

→ 0= (-3k+9)/k+1

-3k+9 = 0

-3k = -9

k=-9/-3

k = 3

and,

y= (2-2k)/k+1

Putting k = 3 now, we get,

y = (2-2*3)/3+1

=(2-6)/ 4

= (-4) / 4

= (-1)

Therefore ratio is k :1 = 3 :1 and point of division is P( 0,-1).