Question

In what ratio is the line joining (2,-4) and (-3,6) divided by the y axis. ​

Answer 1

${\large{\underline{\underline{\bf{Question}}}}}$

In what ratio is the line joining (2,-4) and (-3,6) divided by the y axis.

${\large{\underline{\underline{\bf{Answer}}}}}$

=> 2:3

${\large{\underline{\underline{\bf{Solution}}}}}$

Let the line joining points A(2, -4) and B(-3,6) be divided by point P(0,y) , in the ratio k:1 .

x = $\dfrac{kx2 +k1}{k+1}$

=> 0 = $\dfrac{k×(-3)+q×2}{k+1}$

=> 0 = -3k+2

=> k = $\dfrac{2}{3}$

Thus, the required ratio is $2:3$

Answer 2

${\large{\underline{\underline{\bf{Question}}}}}$

In what ratio is the line joining (2,-4) and (-3,6) divided by the y axis.

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$\textbf{\huge{\red{Solution}} }$

Let the line joining points A(2 , -4) and B(-3 , 6) be divided by point P(0 , y) , in the ratio k:1 .

$\implies$ x = $\dfrac{kx2 + k1}{k + 1}$

$\implies$ 0 = $\dfrac{k × (-3) + q ×2}{k + 1}$

$\implies$ 0 = -3k + 2

$\implies$ k = $\dfrac{2}{3}$

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$\textbf{\huge{\blue{Answer}} }$

Thus , the required ratio is 2:3 .