Question

In what ratio is the line segment joining (1 3) and (2 7) divided by 3x+y-9=0

Answer 1

Let the point (x,y) divides AB in the ratio k:1.

 

By section formula,

x = (2k+1)/(k+1)  ,  y = (7k+3)/(k+1)

 

Now, this point also lies on the given line so it would satisfy the equation 3x+y-9=0

Therefore,

3(2k+1) + (7k+3) -9(k+1) = 0

k = 3/4

Hence, the required ratio is 3:4.

Answer 2

Answer:

Step-by-step explanation: