Question

In what ratio is the line segment joining the points (5,8) and(7,-3) divided by the X-axis and Y-axis.​

Answer 1

Answer:

Step-by-step explanation:

Let the required ratio be k:1=m:n

Point on y- axis would be  (0,y)=(x,y)

By Section Formula,

c(x,y)=(  

m+n

mx  

1

​

+nx  

2

​

 

​

 ,  

m+n

mx  

1

​

+nx  

2

​

 

​

)

Equating x-coordinate,

0=  

k+1

k(−8)+1(5)

​

 

−8k+5=0

   

∴ k=  

8

5

​

 

Required ratio k:1=  

8

5

​

:1  or 5:8 (option B)

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