Question

In what ratio is the line segment joining the points P(-2, -3) and Q(3, 7) divided by the y – axis?

Answer 1

Answer:

The ratio is 2 : 3

Step-by-step explanation:

Slope of the line going through PQ is ($y_{2}$ - $y_{1}$) / ($x_{2}$ - $x_{1}$) = (7-(-3)) / (3-(-2))

m = 2

(y - 7) = 2(x - 3) ⇒ y = 2x + 1

See attachment.

In Δ PQP' : line segment PP' ║ AA' ⇒ PA : AQ = P'A' : A'Q = 4 : 6

In simple form PA : AQ = 2 : 3