Question

in what ratio must an article earth rupees 25 per kg be mixed with another article worth is rupees 40 per kg so that by selling the mixture at rupees 42 per kg a profit of 40% is made​

Answer 1

Answer:

The required ratio is 2:1

Step-by-step explanation:

Let "x" be the quantity in kg of article costing Rs.25 per kg

Let "y" be the quantity in kg of article costing Rs.40 per kg

The total quantity in kg of the mixture = (x + y)

The cost of article costing Rs.25 per kg = 25x

The cost of article costing Rs.40 per kg = 40y

=> Total cost price = 25x + 40y .......(i)

The mixture of is sold at Rs.42 per kg

=> Total selling price = 42(x + y) ....(ii)

We need a profit of 40%. This means that:

SP = CP + 40% of CP

SP = CP + 0.4*CP

SP = 1.4*CP

From (i) and (ii), we get:

42(x + y) = 1.4(25x + 40y)

=> 42x + 42y = 35x + 56y

=> 42x - 35x = 56y - 42y

=> 7x = 14y

=> x = 2y

=> x/y = 2

=> x/y = 2/1

=> x:y = 2:1

Answer: Article costing Rs.25 per kg should be mixed with article costing Rs.40 per kg in the ratio of 2:1 of their weights.