Math, asked by akyadav5304, 10 months ago

In what ratio should a 70% MILK solution to be mixed with a 20% milk solution in order to get a 55% milk solution

Answers

Answered by amitnrw
0

Answer:

7 : 3

Step-by-step explanation:

In what ratio should a 70% MILK solution to be mixed with a 20% milk solution in order to get a 55% milk solution

Let say  Solution one is Taken  100A

& Another Solution is taken 100B

Total Milk = 70A + 20B

Total Solution = 100A + 100B

(70A + 20B)/( 100A + 100B)  = 55/100

=> 70A + 20B = 55A + 55B

=> 15A = 35B

=> 3A = 7B

=> A/B = 7/3

=> A: B :: 7 : 3

in 7: 3 ratio should a 70% MILK solution to be mixed with a 20% milk solution in order to get a 55% milk solution

Answered by abhi178
3

initially, concentration of milk solution is 70% . means in 100ml of solution 70ml of milk in 30ml of water.

Let initial amount of milk is x.

then, milk in solution = 0.7x ml

water in solution = 0.3x ml

now, it is mixed with y ml of 20% milk solution ( where 20y ml milk and 80y ml water). concentration of milk in mixture becomes 55%

then, milk in mixture = (0.7x + 0.2y)ml

and water in mixture = (0.3x + 0.8y) ml

volume of mixture = (x + y)ml

then, concentration of milk = milk in solution/volume of solution × 100

or, 55 = (0.7x + 0.2y)/(x + y) × 100

or, 0.55(x + y) = 0.7x + 0.2y

or, 0.55x + 0.55y = 0.7x + 0.2y

or, 0.35y = 0.15x

or, 3x = 7y

or, x/y = 7/3

hence, answer is 7 : 3

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