In what ratio should a 70% MILK solution to be mixed with a 20% milk solution in order to get a 55% milk solution
Answers
Answer:
7 : 3
Step-by-step explanation:
In what ratio should a 70% MILK solution to be mixed with a 20% milk solution in order to get a 55% milk solution
Let say Solution one is Taken 100A
& Another Solution is taken 100B
Total Milk = 70A + 20B
Total Solution = 100A + 100B
(70A + 20B)/( 100A + 100B) = 55/100
=> 70A + 20B = 55A + 55B
=> 15A = 35B
=> 3A = 7B
=> A/B = 7/3
=> A: B :: 7 : 3
in 7: 3 ratio should a 70% MILK solution to be mixed with a 20% milk solution in order to get a 55% milk solution
initially, concentration of milk solution is 70% . means in 100ml of solution 70ml of milk in 30ml of water.
Let initial amount of milk is x.
then, milk in solution = 0.7x ml
water in solution = 0.3x ml
now, it is mixed with y ml of 20% milk solution ( where 20y ml milk and 80y ml water). concentration of milk in mixture becomes 55%
then, milk in mixture = (0.7x + 0.2y)ml
and water in mixture = (0.3x + 0.8y) ml
volume of mixture = (x + y)ml
then, concentration of milk = milk in solution/volume of solution × 100
or, 55 = (0.7x + 0.2y)/(x + y) × 100
or, 0.55(x + y) = 0.7x + 0.2y
or, 0.55x + 0.55y = 0.7x + 0.2y
or, 0.35y = 0.15x
or, 3x = 7y
or, x/y = 7/3
hence, answer is 7 : 3