Question

in what ratio should a seller mix oilrs. 100 per ltr with oil at 90 per ltr. so that the mixture should worth 92.50 per ltr​

Answer 1

Answer:

Short Trick:

By using the method of alligation,

100 90

92.50

(92.50 - 90) (100 - 92.50)

2.5 : 7.5

1 : 3

Answer 2

Step-by-step explanation:

SOLUTION

First of all, we use given quantities and place them in the formula, to know the required quantities.

Cost of 1 litre oil of first type= Cost price of dearer = d = Rs. 100

Cost of 1 litre oil of second type = Cost price of cheaper = c = Rs. 90

Desired cost of 1 litre of the mixture = Mean price = m = Rs 92.50

$\(\begin{array}{l} {\rm{Required\;rate}} = \frac{{{\rm{Quantity\;of\;Cheaper}}}}{{{\rm{Quantity\;of\;Dearer}}}} = \frac{{{\rm{d}} - {\rm{m}}}}{{{\rm{m}} - {\rm{c}}}}\\ \Rightarrow \frac{{{\rm{Quantity\;of\;Cheaper}}}}{{{\rm{Quantity\;of\;Dearer}}}} = \frac{{100 - 92.50}}{{92.50 - 90}} = \frac{{7.50}}{{2.50}} = \frac{3}{1} \end{array}\)$

∴ The ratio of the mixture should be 1 : 3

Short Trick:

By using the method of alligation,

100 90

92.50

(92.50 - 90) (100 - 92.50)

2.5 : 7.5

1 : 3