in what ratio x-y-2=0 divides the line segment joining points A(3,-1) and C(0,2)
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Hi Army Girl
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Let A(3,-1) and B(8,9).
Let the line x−y−2=0 divide the line segment AB at point C(x,y) in the ratio m:n.
By section formula,
C(x,y)=[ m+nm×8+n×3, m+n,m×9+n×−1 ]
C(x,y)= [ m+n8m+3n, m+n9m−n ]
Since, point C lie on the line x−y−2=0,
8m+3n 9m-n
———— – ———— –2 = 0
m+n m+n
8m+3n−9m+n−2m−2n=0
3m=2n
m 2
—— = —
n 3
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