Math, asked by karthikpandu7151, 11 months ago

In what time 5600 amount to 6720 at 8% per annum?

Answers

Answered by Anonymous
21

Answer:

\large\bold\red{2.5\:yrs.}

Step-by-step explanation:

Given,

  • Principal, p = ₹ 5600
  • Amount, a = ₹ 6720

But,

We know that

  • Simple intrest = Amount - Principal

Therefore,

We get,

  • S.I = ₹ (6720 - 5600) = ₹ 1120

Also,

  • Rate of interest p.a , r = 8%

Now,

Let the time taken is t yrs.

Therefore,

We get,

 =  > 1120 =  \frac{5600 \times8 \times t }{100}  \\  \\  =  > t =  \frac{1120 \times 100}{5600 \times 8}  \\  \\  =  > t =  \frac{112 \times 10}{56  \times 8}  \\  \\  =  > t =  \frac{56 \times 20}{56 \times 8}  \\  \\  =  > t =  \frac{20}{8}  \\  \\  =  > t =  \frac{5}{2} \\  \\  =  > t = 2.5

Hence,

The required time is 2.5 yrs.

Answered by MissAlison
35

Answer:

Hope it will help :)♥️♥️

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