Question

In what time a sum will be 29/10times of itself at 5%p.a. S.I

Answer 1

Answer:

38 Years

Step-by-step explanation:

Let the Principal be ₹100

So, Amount will be = $\Large{\frac{29}{10}}$ of Principal

= $\Large{\frac{29}{10}}$ × 100

= ₹290

S.I = Amount - Principal

= 290 - 100

= ₹190

Formula :

T = $\Large{\frac{SI × 100}{P × R}}$

= $\Large{\frac{190×100}{100×5}}$

= $\large{\boxed{38\:years}}$

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Mark Brainliest, if it helps.